1/2x^2-22/9x-16/9=0

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Solution for 1/2x^2-22/9x-16/9=0 equation: 


x in (-oo:+oo)

(1/2)*x^2-((22/9)*x)-(16/9) = 0

(1/2)*x^2+(-22/9)*x-16/9 = 0

1/2*x^2-22/9*x-16/9 = 0

DELTA = (-22/9)^2-(-16/9*1/2*4)

DELTA = 772/81

DELTA > 0

x = ((772/81)^(1/2)+22/9)/(1/2*2) or x = (22/9-(772/81)^(1/2))/(1/2*2)

x = (772/81)^(1/2)+22/9 or x = 22/9-(772/81)^(1/2)

x in { 22/9-(772/81)^(1/2), (772/81)^(1/2)+22/9 }

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